# Hypothesis testing for pmcc (A-level Maths)

This is the third of my series of three articles on hypothesis testing for A-level Maths, and covers hypothesis testing for pmcc (the product moment correlation coefficient).

The first instalment introduced the concept of hypothesis testing and covered hypothesis testing for a binomial distribution, and can be found here; the second covered hypothesis testing for the mean of a normal distribution and can be found here.

You might be surprised to learn that hypothesis testing for pmcc, although usually the last to be covered, is actually the simplest.

## Hypothesis testing for pmcc

### The purpose of hypothesis testing

A hypothesis test for pmcc is to establish whether the correlation found in a sample indicates that correlation is likely to exist in the population as a whole.

For example, a survey of a random sample of 30 adults from a particular region might show a positive correlation between head circumference and score in an IQ test, with a pmcc of 0.57. We can use a hypothesis test to ascertain whether this means that correlation between head circumference and IQ test result probably exists across the entire population of that region.

### How it works – basic principle

H_{0} is the null hypothesis, which is the assertion that there is no correlation in the population as a whole. Just as is used to represent the product moment correlation coefficient for an observed sample, the equivalent Greek letter (lowercase rho) is used for the pmcc of the whole population (similar to using and the Greek (lowercase mu) respectively for a sample mean and the population mean of a distribution).

So when we’re testing for pmcc, the null hypothesis is always that , i.e. that there is no correlation in the population as a whole.

H_{1} is the alternative hypothesis, which is the assertion that the correlation *does *exist in the population as a whole. If the hypothesis specifies whether the correlation is positive () or negative () then it’s a 1-tailed test; if not – effectively H_{1} is sitting on the fence and not committing either way – then it’s a 2-tailed test where .

We use tables to look up the critical value of that would indicate correlation in the population as a whole, and compare it with the pmcc of the observed sample. If the magnitude of the observed pmcc is greater than the critical value then the result is significant, so we reject H_{0} and accept that correlation probably does exist across the whole population.

** Note: **Because it’s all based on a balance of probabilities, you can never make a definitive statement that yes, correlation

*exist in the population, only that it’s*

**does****that it does. Therefore the question is always whether we**

*likely***reject H**, not whether we accept H

_{0}_{1}.

### The critical value

Of course, the smaller the sample, the higher the critical value of ; if you only have six items in your sample then you’re much more likely to observe a correlation in your sample where none exists in the whole population, than if you had a sample of 60. And the significance level also affects the critical value: a lower value of α means a more demanding test and therefore a higher critical value.

Edexcel provides a table (on page 37 of the formula booklet) for you to look up the critical value; see extract below. AQA doesn’t provide such a table, but when they’ve asked questions on hypothesis testing for pmcc they’ve included a few values so that you still had to identify the right one. I’m not sure which approach OCR takes to this topic.

For example, if you had a sample size of 12 and a significance level of 5% then the critical value would be 0.4973, so if the magnitude of the observed sample’s pmcc was greater than this then you’d reject H_{0}.

As with other hypothesis tests, the significance level is also **the probability of incorrectly rejecting H _{0}**. This is because although it may be

*probable*that correlation exists in the population as a whole, it is still

*possible*that it doesn’t.

## Hypothesis testing for pmcc: Method

The writing frame below shows you how to present your answer to a question on hypothesis testing for pmcc. (Scroll down for a plain text version.) You can get a free printable copy – as well as other useful downloads – if you sign up to my mailing list – see this page.

#### Writing frame (plain text version: p-value method)

- Write down the test statistic, , for the sample
- Write down the null and alternative hypotheses.
- State the significance level α. If it’s a 2-tailed test then use half of this value.
- Look up the critical value for the given significance level and sample size
- Compare to the critical value and write conclusion: reject H
_{0}is magnitude of > critical value. Remember to include context!- Since [
*value of*]**<**/**>**[*critical value of α or***<***α/2 as appropriate*], the result is**significant**/**not significant**. There is**sufficient**/**insufficient**evidence at the [*α%*] level of significance to reject H_{0}and support the claim that …

- Since [

## Example

For a data sample of 10 items showing a pmcc of -0.69 between BMI (body mass index) and walking speed, carry out a hypothesis test to ascertain

(a) at the 1% level of significance, whether correlation exists in the population as a whole;

(b) at the 5% level of significance, whether negative correlation exists.

(The model solutions below use the writing frame above.)

#### Solution to (a)

H_{0}:

H_{1}: [This is a 2-tailed test since the direction is not specified]

Significance level α = 0.01 but test is 2-tailed so use 0.005

From the table, critical value = 0.7646

Since |-0.69| < 0.7646, the result is not significant.

Conclusion: There is insufficient evidence at the 1% level of significance to reject H_{0} and support the claim that there is correlation between BMI and walking speed in the population as a whole.

#### Solution to (b)

H_{0}:

H_{1}: [This is a 1-tailed test since the direction is specified]

Significance level α = 0.05

From the table, critical value = 0.5494

Since |-0.69| < 0.5494, the result is significant.

Conclusion: There is sufficient evidence at the 5% level of significance to reject H_{0} and support the claim that there is negative correlation between BMI and walking speed in the population as a whole.

## Your turn

The height and average length of sleep of 12 adults is measured and the pmcc calculated as 0.52. Carry out hypothesis tests to ascertain

(a) at the 10% level of significance, whether there is positive correlation in the population;

(b) at the 5% level of significance, whether correlation exists in the population as a whole.

Work through the writing frame, using the example solution above as a model, then check your answers by clicking on the link below.

That covers all the hypothesis testing you need for A-level Maths.

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#### Answers:

##### Your turn (a)

H_{0}:

H_{1}: [This is a 1-tailed test since the direction is specified]

Significance level α = 0.10

From the table, critical value = 0.3981 (for n=12 and α=0.10)

Since 0.52 > 0.3981, the result is significant.

Conclusion: There is sufficient evidence at the 10% level of significance to reject H_{0} and support the claim that there is positive correlation between height and length of sleep in the population as a whole.

##### Your turn (b)

H_{0}:

H_{1}: [This is a 2-tailed test since the direction is not specified]

Significance level α = 0.05 but test is 2-tailed so use 0.025

From the table, critical value = 0.5760 (for n=12 and α=0.025)

Since 0.52 < 0.5760, the result is not significant.

Conclusion: There is insufficient evidence at the 5% level of significance to reject H_{0} and support the claim that correlation between height and length of sleep in the population as a whole.